Relativity question involving time dilation

In summary: In this case, you are using seconds, so you must write Δt = 2.2 s. In general, parentheses are used to make formulas readable. They are also necessary for the formula to be unambiguous, because they tell you what the formula is supposed to be. You can't just have a bunch of numbers and operators without any grouping. In your case, you have an incorrect formula. It should be Δtm = Δts / √ (1 - v2 / c2). You are forgetting to take the square root. Also, I have no idea where you got the formula. You should write out the full name of the formula so that I can check it.
  • #1
MiniOreo1998
18
0

Homework Statement


A muon has a lifetime of 2.20 x 106 s when at rest, after which time it decays into other particles.

A) Ignore any effects of relativity discussed in this section. If the muon was moving at 0.99 c, how far would it travel before decaying into other particles, according to Newtonian mechanics?

B) How long would the muon last, according to an observer in Earth's reference frame or referenced who viewed the muon moving at 0.99 c?

C) How far would the muon actually travel, when viewed moving at 0.99 c?

D) Compare the two distances travelled. Explain why this type of evidence is excellent support for the theory of relativity.

I'm unsure of B and C. Any help would be appreciated!

Homework Equations


Δtm = Δts / √ 1 - v2 / c2

The Attempt at a Solution



A)
0.99 (3 x 108 = 2.97 x 10 8
2.97 x 10 8 (2.20 x 10 -6 = 653.4

B)
Δtm = Δts / √ 1 - v2 / c2
Δtm = 2.20 x 10-6 / 1 - 0.99 (3.0 x 108)2
Δtm = 9.8 x 10-6

C)
0.99 (3 x108 (9.8 x 10-6= 2910.6 m

D) As the particle approaches the speed of light time dilation becomes more prevalent, causing the muon to last longer
 
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  • #2
MiniOreo1998 said:
Δtm = Δts / √ 1 - v2 / c2
Δtm = 2.20 x 10-6 / 1 - 0.99 (3.0 x 108)2

Your math is off. It is also impossible to tell exactly what you are doing because you are not writing out parentheses and units properly. Parentheses are important in order for your expressions to be readable to anyone, including yourself. Physical quantities always has units. You cannot say that Δt = 2.2 without specifying which units you are using.
 

Related to Relativity question involving time dilation

1. What is time dilation in the context of relativity?

Time dilation is a phenomenon predicted by Einstein's theory of relativity, which states that time passes slower for objects moving at high speeds or in strong gravitational fields. This means that time can be perceived differently by observers in different frames of reference.

2. How does time dilation affect our daily lives?

Since the effects of time dilation are only noticeable at extremely high speeds or in strong gravitational fields, it does not have a significant impact on our daily lives. However, it is a crucial factor to consider in GPS technology and satellite communication systems, as they operate at high speeds and need to account for the differences in time between Earth and space.

3. Can time really slow down or speed up?

Time dilation is not a physical slowing down or speeding up of time, but rather a difference in the perceived passage of time between observers in different frames of reference. This effect has been proven through various experiments and is a fundamental concept in the theory of relativity.

4. Does time dilation apply to all types of clocks?

Yes, time dilation affects all clocks, regardless of their mechanism. This means that even atomic clocks, which are known for their accuracy, will experience time dilation if they are in motion or in a strong gravitational field.

5. Can time dilation be reversed?

No, time dilation is a fundamental aspect of the theory of relativity and cannot be reversed. It is a consequence of the way space and time are intertwined in the fabric of the universe, and any attempt to reverse it would go against the laws of physics.

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