- #1
ladyrae
- 32
- 0
Help!
My problem asks to find the vertical asymptotes of x^3/(x^2+3x-10)
I found –5 & 2 to be vertical asymptotes but what I can’t figure out is
how as x->-5- = -oo and x->-5+ = +oo
I have calculated lim x->-5+ x^3/(x^2+3x-10) = -125/(0)(-5 - -2) = -125/-0 = +oo
But I don’t see –oo lim x->+5+ x^3/(x^2+3x-10) = ?
Can you show me the algebra and how the signs work out to give me –oo
Thanks
My problem asks to find the vertical asymptotes of x^3/(x^2+3x-10)
I found –5 & 2 to be vertical asymptotes but what I can’t figure out is
how as x->-5- = -oo and x->-5+ = +oo
I have calculated lim x->-5+ x^3/(x^2+3x-10) = -125/(0)(-5 - -2) = -125/-0 = +oo
But I don’t see –oo lim x->+5+ x^3/(x^2+3x-10) = ?
Can you show me the algebra and how the signs work out to give me –oo
Thanks