- Thread starter
- #1

- Thread starter shorty888
- Start date

- Thread starter
- #1

- Mar 1, 2012

- 249

Do you mean $f(x) = \frac{6x^2-17x-3}{3x+2}$F(x)= 6x^2-17x-3/3x+2, find horizontal asymptote

A horizontal asymptote is a line where a function approaches but doesn't quite reach there. An example is y=0 for f(x) = e^x

There are no horizontal asymptotes in your case, there is a vertical one where 3x+2 = 0 but no horizontal ones.

nb: Please take care with brackets, I've guessed at what you meant but that isn't the literal meaning of what you wrote which would be $F(x) = 6x^2-17x-x+2$

- Thread starter
- #3

Yes I mean fraction

F(x)= 6x^2-17x-3/3x+2, find horizontal asymptote

- Jan 26, 2012

- 66

There is also a diagonal asymptote but a word from the OP will be required to find out if such asymptotes have been taught.Do you mean $f(x) = \frac{6x^2-17x-3}{3x+2}$

A horizontal asymptote is a line where a function approaches but doesn't quite reach there. An example is y=0 for f(x) = e^x

There are no horizontal asymptotes in your case, there is a vertical one where 3x+2 = 0 but no horizontal ones.

nb: Please take care with brackets, I've guessed at what you meant but that isn't the literal meaning of what you wrote which would be $F(x) = 6x^2-17x-x+2$