- #1
Matt H
- 7
- 0
question(s):
These are questions from an exam i took earlier tonight, but do not know if i got them correct.
1) Rain is falling with velocity 30 m/s at an angle of 60° from the vertical and is blowing due east. If a passenger inside of a train (also traveling due east) observes the rain falling at an angle of 30° from the vertical how fast is the train moving?
2) Conceptual: Does a bullet fired on Earth and a bullet fired on the moon have the same final velocity?
equations:
Trig rules and vector knowledge...
attempt at solution:
What I'm doing as of now is drawing a right triangle with the hypoteneuse equaling 30 m/s, the angle from the vertical equaling 30° and the angle from the horizontal equaling 60° (a standard 30:60:90 triangle). Then, I'm just using standard trig rules to solve for the "opposite" side which in this case i believe would represent the velocity of the train. If that is a correct solution then the answer should be easily gotten by solving this:
sin30°= x / 30 m/s
30(sin30°) = x
15 = x
A choice on the exam was 14.9 so that is what i chose. I just don't know if that is a valid way to do the problem or not...
These are questions from an exam i took earlier tonight, but do not know if i got them correct.
1) Rain is falling with velocity 30 m/s at an angle of 60° from the vertical and is blowing due east. If a passenger inside of a train (also traveling due east) observes the rain falling at an angle of 30° from the vertical how fast is the train moving?
2) Conceptual: Does a bullet fired on Earth and a bullet fired on the moon have the same final velocity?
equations:
Trig rules and vector knowledge...
attempt at solution:
What I'm doing as of now is drawing a right triangle with the hypoteneuse equaling 30 m/s, the angle from the vertical equaling 30° and the angle from the horizontal equaling 60° (a standard 30:60:90 triangle). Then, I'm just using standard trig rules to solve for the "opposite" side which in this case i believe would represent the velocity of the train. If that is a correct solution then the answer should be easily gotten by solving this:
sin30°= x / 30 m/s
30(sin30°) = x
15 = x
A choice on the exam was 14.9 so that is what i chose. I just don't know if that is a valid way to do the problem or not...
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