Radius of a circle that intersects two points on a right triangle.

In summary, to determine the radius of a circle that intersects two points on a right triangle, you can use coordinate geometry. Let the point where the triangle is tangent to the circle be the origin and the side of the circle parallel to the x-axis. From there, you can use the equation of the circle and the coordinates of the point where the triangle touches the circle to find the radius. Another method is to create a square with one side being the radius of the circle and the other side being the distance between the triangle's vertex and the point where it intersects the circle. Then, using Pythagoras' theorem, you can solve for the radius.
  • #1
dgoldman86
3
0
I'm trying to figure out the radius of a circle that intersects two points on a right triangle. One side of the triangle is tangent to the circle and the other intersects it. I have attached an image that helps further explain what I'm talking about. Knowing what I have listed in the image is there anyway to determine the radius of that circle?

Thanks.
 

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  • #2
Try using coordinate geometry. Let the point where the triangle is tangent to the circle be the origin, and let that side of the circle run parallel to the x-axis. What's the equation of the circle? What are the coordinates of the point where the triangle touches the circle?
 
  • #3
How about this

Call the vertex of your right triangle [itex](c_1,r,c2)[/itex] with [itex]c_1[/itex] tangent to the circle and [itex]r[/itex] the vertex at the right angle. Let [itex]o[/itex] be the center of your circle.
Now construct the square [itex](o,c_1,r,s)[/itex].
Observe that [itex]c_2[/itex] is on the square side [itex](r,q)[/itex] and use pythagoras.
 

Related to Radius of a circle that intersects two points on a right triangle.

1. What is the formula for finding the radius of a circle that intersects two points on a right triangle?

The formula for finding the radius of a circle that intersects two points on a right triangle is r = (a*b*c) / (4*∆), where r is the radius, a, b, and c are the sides of the triangle, and ∆ is the area of the triangle.

2. How do you determine if a circle intersects two points on a right triangle?

A circle intersects two points on a right triangle if the distance between the center of the circle and each of the two points is equal to the radius of the circle. This can be determined using the Pythagorean theorem.

3. Can the radius of a circle that intersects two points on a right triangle be negative?

No, the radius of a circle cannot be negative. It represents the distance from the center of the circle to its edge, so it must always be a positive value.

4. Is there a simpler way to find the radius of a circle that intersects two points on a right triangle?

Yes, if you know the coordinates of the two points on the triangle and the coordinates of the center of the circle, you can use the distance formula d = √((x2-x1)^2+(y2-y1)^2) to find the radius.

5. Can the radius of a circle that intersects two points on a right triangle be larger than the hypotenuse of the triangle?

Yes, it is possible for the radius of a circle to be larger than the hypotenuse of the triangle. This would occur when the two points on the triangle are close to the same side and the center of the circle is far from the triangle.

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