- Thread starter
- #1

#### bergausstein

##### Active member

- Jul 30, 2013

- 191

can you tell the difference

$\displaystyle \sqrt{(1)^2}=1$

$\displaystyle \sqrt{(-1)^2}=-1$

$\displaystyle \sqrt{(1)^2}=1$

$\displaystyle \sqrt{(-1)^2}=-1$

- Thread starter bergausstein
- Start date

- Thread starter
- #1

- Jul 30, 2013

- 191

can you tell the difference

$\displaystyle \sqrt{(1)^2}=1$

$\displaystyle \sqrt{(-1)^2}=-1$

$\displaystyle \sqrt{(1)^2}=1$

$\displaystyle \sqrt{(-1)^2}=-1$

- Admin
- #2

- Jan 29, 2012

- 1,151

The major difference is that the first one is right and the second one is wrong! Both [tex](1)^2[/tex] and [tex](-1)^2[/tex] are equal to 1 so both of those is [tex]\sqrt{1}[/tex]. And [tex]\sqrt{a}[/tex] is defined as thecan you tell the difference

$\displaystyle \sqrt{(1)^2}=1$

$\displaystyle \sqrt{(-1)^2}=-1$