Radial acceleration: Rotating Carousel

In summary: I'm glad the answer seems reasonable. You do not need to consider the gravitational and normal forces since they cancel each other out in this scenario. The only net force acting on the child is the centripetal force, which is equal to the calculated value of 59.9N.
  • #1
paxian
14
0

Homework Statement


A horse located 8.0m from the central axis of a rotating carousel moves at a speed of 6.0 m/s. The horse is at a fixed height (it does not move up or down). What is the net force acting on a child seated on this horse? The child weight is 130N.


Homework Equations


net force = ma= mv^2/r
weight = mg

The Attempt at a Solution


m = 130N/(9.8m/s^2)=13.3kg
net force = 13.3kg *(6m/s)^2/8.0m = 59.9N

I think the answer 59.9N seems reasonable... However, I am wondering if I need to do anything with the gravitation force - Weight and the normal force
like: netforce= N - W= ma
N=W+ma?
 
Physics news on Phys.org
  • #2
If the horse does not move up or down, then it has a net force of 0. This means that the gravitational and normal force cancel each other out. As a result, the only net force acting on the child is the centripetal force you found, the 59.9N.
 
  • #3
MrNerd said:
If the horse does not move up or down, then it has a net force of 0. This means that the gravitational and normal force cancel each other out. As a result, the only net force acting on the child is the centripetal force you found, the 59.9N.

Thank you!
 

Related to Radial acceleration: Rotating Carousel

What is radial acceleration and how does it relate to a rotating carousel?

Radial acceleration is the acceleration experienced by an object moving in a circular path. On a rotating carousel, this acceleration is constantly changing direction and magnitude, as the object is constantly changing direction and speed.

How is radial acceleration calculated on a rotating carousel?

The formula for calculating radial acceleration is a = v^2/r, where a is the radial acceleration, v is the tangential velocity, and r is the radius of the circular path. On a rotating carousel, the tangential velocity is constantly changing, so the radial acceleration is also constantly changing.

Why do passengers on a rotating carousel feel a force pushing them outwards?

This is due to the centrifugal force, which is a result of the radial acceleration. As the object moves in a circular path, it experiences a force that pulls it outwards from the center of the circle. This force is what causes passengers to feel pushed outwards on a rotating carousel.

What happens to the radial acceleration if the speed of the rotating carousel is increased?

If the speed of the rotating carousel is increased, the tangential velocity of the objects on the carousel will also increase. This means that the radial acceleration will also increase, as it is directly proportional to the tangential velocity.

How does the radius of the rotating carousel affect the radial acceleration?

The radius of the rotating carousel affects the radial acceleration in an inverse relationship. As the radius increases, the radial acceleration decreases, and vice versa. This is because a larger radius means a longer distance to travel in a circular path, which results in a lower tangential velocity and therefore a lower radial acceleration.

Similar threads

Replies
6
Views
874
  • Introductory Physics Homework Help
Replies
7
Views
369
  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
215
  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
2K
Back
Top