R parity conserving susy models

[Amith2006]

Hi,
I was going through the concept of R parity in SUSY. In the case of SUSY we do not have Baryon and Lepton number conservation instead we have R parity conservation defined by,
R-parity= (-1)^2s+3B+L
which is required for the proton to be stable. But it has been found that this condition need not be satisfied for proton stability. Instead we can have either Lepton number or Baryon number conserving terms in the Lagrangian which serves the purpose. My question is- 'There are so many SUSY models and so can we have any model to be R parity conserving or violating by the same recipe'? Thanks.

 

[AndyW]

Hello,

Thank you for bringing up the concept of R parity in SUSY. R parity conservation is indeed an important aspect of supersymmetry and plays a crucial role in the stability of the proton. However, as you mentioned, it is not the only way to ensure proton stability.

There are indeed many SUSY models and each one of them may have different R parity conservation or violation properties. This is because R parity is a theoretical concept and not a fundamental symmetry of nature. It is a useful tool for organizing the particles in a SUSY theory and for understanding their interactions, but it is not a requirement for the theory to work.

In fact, there are some models where R parity is explicitly violated, and yet the theory remains consistent and can explain observed phenomena. This is because R parity is not a fundamental law of nature, but rather a constraint that we impose on our theoretical models.

Therefore, it is possible to have SUSY models that are R parity conserving or violating, depending on the specific model and its parameters. It is also possible to have models that have a mix of R parity conserving and violating terms, as long as they still satisfy the conditions for proton stability.

I hope this helps to clarify your question. Thank you for your interest in supersymmetry and its implications for particle physics.