- #1
Kevin McHugh
- 318
- 164
Given the definition:
δ(x) = 0 for all x ≠ 0
∞ for x = 0
∫-∞∞δ(x)dx = 1
I don't understand how the integral can equal unity. The integral from -∞ to zero is zero, and the integral from 0 to ∞ is zero. How can one integrate the discontinuity at zero to equal one? What am I missing? TIA for your insight.
δ(x) = 0 for all x ≠ 0
∞ for x = 0
∫-∞∞δ(x)dx = 1
I don't understand how the integral can equal unity. The integral from -∞ to zero is zero, and the integral from 0 to ∞ is zero. How can one integrate the discontinuity at zero to equal one? What am I missing? TIA for your insight.