Question regarding energy from chemicals (M.C.Q)

[hamxa7]

Q. A volume of 100 cm3 of 1 mol dm3 sodium hydroxide solution was added to 100 cm3 of 1 mol dm3 hydrochloric acid.The maximum rise in temperature recorded was T1.The experiment was repeated with 50cm3 of each solution and the rise in temperature this time was T2. It is found That


A) T1 Is Equal To T2
B) T1 Is Half The value Of T2
C) T2 is half the value of T1
D) T2 Is a quarter the value of T1.


I think the Ans Should Be C as the volume is decreased...
What do you think as the answer given is A...

reply quickly... :-)

 

[phyzguy]

The volume is decreased, but the total energy of reaction is decreased in proportion. Remember energies of reaction are per mole, so if you cut the number of moles of reactant in half, the total energy liberated is also cut in half.

 

[hamxa7]

can you explain it in further detail...
examples would be appreciated..

 

[Borek]

Assume 1 mole of NaOH reacting with 1 mole HCl liberates energy Q. Calculate how much energy is liberated in both cases (in terms of Q). Calculate masses of solution in both cases. Calculate ratio of energy liberated to final mass of the solution for each case (again in terms of Q, assume density of 1g/mL). What did you get?

 

[DeeNos]

I cannot provide a definitive answer without more information about the experiment and the conditions under which it was conducted. However, based on the given information, it is likely that the answer is A) T1 is equal to T2. This is because the experiment was repeated with equal volumes of the two solutions, and the rise in temperature was recorded for both trials. In this case, it is expected that the rise in temperature would be proportional to the amount of reactants present, regardless of the volume of the solutions. Therefore, T1 and T2 should be equal. However, without knowing more about the experiment, it is not possible to say for certain.