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matsci0000
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Que- A uniform chain of length L and mass m is held on a smooth table with one-fourth of its length hanging over the edge. If g is the acceleration due to gravity, find the work required to pull the hanging part on the table.
CHECK MY SOLUTION---------AND POINT OUT MY MISTAKE.
Weight of the hanging part of the chain=mg/4
Therefore, work done=(mg/4)(L/4)
=mgL/16...Answer
I am getting this answer. But the correct answer is mgL/32.
Is there any role of center of mass in this question?
CHECK MY SOLUTION---------AND POINT OUT MY MISTAKE.
Weight of the hanging part of the chain=mg/4
Therefore, work done=(mg/4)(L/4)
=mgL/16...Answer
I am getting this answer. But the correct answer is mgL/32.
Is there any role of center of mass in this question?