Question on the degeneracies of a thermodynamic system

In summary, the system has three energy levels with degeneracies of 1 and 2, and the heat capacity can be found by calculating the expectation value of the internal energy and taking its derivative with respect to temperature. The partition function and the concept of degeneracies are necessary steps in this process.
  • #1
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Homework Statement


A system possesses three energy levels $$E_1=\varepsilon$$ $$E_2=2\varepsilon$$ $$E_3=3\varepsilon$$ with degeneracies $$g(E_1)=g(E_3)=1$$ $$g(E_2)=2$$. Find the heat capacity of the system.

Homework Equations


$$\beta=\frac{1}{kT}$$
$$Z=\sum_i g_ie^{-\beta \varepsilon_i} \ $$

The Attempt at a Solution


From a beginner's perspective I know to apply the partition function for a system with degeneracies as the first step in order to be able to obtain more information about the system. Thus,

$$Z=g_ie^{-\beta \varepsilon} + 2g_ie^{-\beta 2\varepsilon} + g_ie^{-\beta 3\varepsilon}$$

But I still don't quite understand what's going on here. Also, the hint at the back of the book (Statistical Physics by F. Mandl) simply says to take the zero of the energy scale at $E_1=0$ and then proceeds to give the final answer as: $$C=2k\frac{x^2e^x}{(e^x+1)^2}$$

But this isn't really helpful in understanding the concept. What do the degeneracies of a system do to the solution of the partition function?
 
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  • #2
Heat capacity is the heat added per change in temperature. So find the expectation value of the internal energy as a function of temperature, and then take its derivative with respect to temperature.
 

Related to Question on the degeneracies of a thermodynamic system

1. What is a degenerate state in a thermodynamic system?

A degenerate state in a thermodynamic system is a state in which the system has the same energy but different configurations. This means that the system can have multiple ways of achieving the same energy level.

2. How do degeneracies affect the behavior of a thermodynamic system?

Degeneracies play a crucial role in determining the entropy of a thermodynamic system. The more degenerate states a system has, the higher its entropy will be. This is because a higher number of degenerate states means a higher number of possible configurations, leading to a higher level of disorder in the system.

3. Can degeneracies ever be eliminated in a thermodynamic system?

No, degeneracies cannot be eliminated in a thermodynamic system. This is because they are a fundamental property of the system and are a result of the statistical nature of thermodynamics. However, some systems may have a very small number of degenerate states, making them effectively non-degenerate.

4. How do degeneracies relate to the concept of equilibrium in a thermodynamic system?

In a thermodynamic system, equilibrium is achieved when the system has reached its maximum entropy. Degeneracies play a key role in determining the maximum entropy of a system. At equilibrium, the number of degenerate states is at its maximum, meaning that the system has the highest level of disorder.

5. Can degeneracies have an impact on the macroscopic properties of a thermodynamic system?

Yes, degeneracies can have a significant impact on the macroscopic properties of a thermodynamic system. As mentioned earlier, a higher number of degenerate states leads to a higher entropy, which in turn affects other properties such as temperature, pressure, and volume. Degeneracies also play a role in determining the stability and phase transitions of a system.

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