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Question on Stoichiometry

Dhamnekar Winod

Active member
Nov 17, 2018
103
Hi,
If any member knows the correct answer to the following question on stoichiometry, may reply to this question.
SharedScreenshotstoichoimetry.jpg
 
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Klaas van Aarsen

MHB Seeker
Staff member
Mar 5, 2012
8,736
Hey Dhamnekar,

The volume of a gas only depends on the number of molecules given the same pressure and temperature (give or take a little).
It's why we have a molar volume at standard pressure and temperature ($V_m$), which is the volume of 1 mole of gas irrespective of which gas it is.

The volume of $\ce{SO2(g)}$ before the reaction is $10.0\,\text{dm}^3$.
The volume of $\ce{O2(g)}$ is $6.0\,\text{dm}^3$ of which only $5.0\,\text{dm}^3$ will be used (half of $10.0\,\text{dm}^3$).
After the reaction we have the same number of molecules of $\ce{SO3(g)}$, so its volume will be the same. That is, $10.0\,\text{dm}^3$.
 
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