Question involving Newton's laws

In summary: If you don't have the mass, it's hard to find the angle and therefore the sine. Thanks for the explanation.In summary, the surface of the ramp pushes onto the ball with a force of .82 mg.
  • #1
mlb2358
16
0

Homework Statement


A horizontal wire holds a solid uniform ball of mass m in place on a tilted ramp that rises 35.0° above the horizontal. The surface of this ramp is perfectly smooth, and the wire is directed away from the center of the ball.(a) How hard does the surface of the ramp push
on the ball? (b) What is the tension in the wire?


Homework Equations





The Attempt at a Solution


I drew a picture and made a triangle with the normal force as one side, the ramp as one side, and the weight as the hypotenuse. I believe the angle between the ramp and the hypotenuse is 55 degrees. That would mean sin(55) = N/mg and that N = mg*sin(55). This is equivalent to approximately 0.82mg. However, the answer I have for this problem is 1.22mg and 1/sin(55) equals 1.22. I am trying to figure out what I am doing wrong here. Any help would be appreciated!
 
Physics news on Phys.org
  • #2
I am confused as to what you are looking for. You found an answer where you listed your attempt, but you didn't provide a mass to use. Otherwise:

FN = mgsinθ

However, without the knowing the mass, it would be hard to find out where you went wrong.
 
  • #3
Thanks for the reply.
I didn't list a mass because the question didn't provide one. The answer is expected to be in terms of mg. The answer is supposed to be 1.22mg, but I am getting an answer of .82mg.
 
Last edited:
  • #4
Strangely enough, I had a problem like this in my physics course a few weeks ago that took me a while to actually understand. I'm not sure if I can explain it, but the way that I understand it is that when on a plane, FN is represented by a leg of the triangle, and gravity by the hypotenuse. In order to solve this triangle, you must divide by the sine.
 
  • #5


Your approach is correct, but you made a small error in your calculation. The angle between the ramp and the hypotenuse is not 55 degrees, but rather 35 degrees (as stated in the problem). Therefore, the correct equation would be sin(35) = N/mg, which results in N = mg*sin(35). This is equivalent to approximately 0.57mg, which is closer to the given answer of 1.22mg. Always make sure to double check the given information and units when solving a physics problem. Keep up the good work!
 

Related to Question involving Newton's laws

1. What are Newton's three laws of motion?

Newton's first law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. The second law states that the force acting on an object is equal to its mass multiplied by its acceleration. The third law states that for every action, there is an equal and opposite reaction.

2. How do Newton's laws apply to everyday life?

Newton's laws can be seen in everyday life, such as when a ball rolls down a hill (first law), when a car accelerates (second law), or when a balloon pushes air out and moves in the opposite direction (third law).

3. What is the difference between mass and weight in relation to Newton's laws?

Mass is a measure of the amount of matter in an object, while weight is a measure of the force of gravity on an object. Newton's second law, which relates force, mass, and acceleration, applies to both mass and weight.

4. How does Newton's first law explain why objects in space continue to move?

Newton's first law states that an object will remain in motion unless acted upon by an external force. In space, there is no air resistance or other forces to slow down objects, so they continue to move at a constant velocity.

5. Can Newton's laws be broken?

No, Newton's laws are fundamental principles of physics and have been repeatedly tested and proven to be accurate. However, there may be situations where they appear to be broken due to external factors that are not taken into account.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
965
  • Introductory Physics Homework Help
Replies
5
Views
423
  • Introductory Physics Homework Help
Replies
15
Views
359
  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
12
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
353
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
6K
  • Introductory Physics Homework Help
Replies
8
Views
14K
Back
Top