- #1
subhradeep mahata
- 120
- 13
- Homework Statement
- 0.9546 g of a sample of Rochelle salt (NaKC4H4O6.4H2O), on ignition, gave NaKCO3, which was treated with 41.72 mL of 0.1307 N H2SO4. The unreacted H2SO4 was then neutralized by 1.91 mL of 0.1297 N NaOH. Find the percentage purity of the salt in the sample. Use equivalent concept.
- Relevant Equations
- meq of H2SO4 reacted = total meq - unreacted meq=meq of salt
unreacted meq of H2SO4 = meq of NaOH
Using the given formula, meq of H2SO4 reacted= meq of salt = 5.205
The math is correct and I have verified it.
Now, I am pretty sure that I am making a mistake in calculating the n- factor of the salt.
According to the question, C4+6=4C+4
The n- factor is coming out to be 10, which is pretty weird (now, I might be wrong here, maybe there's nothing weird in it. Please also tell me about it's limits)
Now, on doing further calculations, we get the weight as 0.1467g, and the percentage purity is coming out to be 15.3%.
But the answer according to my book is 76.87%.
Can you tell me where I went wrong?
The math is correct and I have verified it.
Now, I am pretty sure that I am making a mistake in calculating the n- factor of the salt.
According to the question, C4+6=4C+4
The n- factor is coming out to be 10, which is pretty weird (now, I might be wrong here, maybe there's nothing weird in it. Please also tell me about it's limits)
Now, on doing further calculations, we get the weight as 0.1467g, and the percentage purity is coming out to be 15.3%.
But the answer according to my book is 76.87%.
Can you tell me where I went wrong?