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bioengi12345
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Homework Statement
A Ladder weighs 20 Lbs. IT rests against a smooth wall at point B. Theta=45. If you pull the ladder at its midpoint, how much force is needed to make it slide at point A? u=.6.The ladder is 15 ft long, Point b is the top and point A is the bottom. 45 Deg is the bottom angle.
Force of pull= 20lb. Now i think the number worked out this was just cause the angle is 45 degrees and gravity as well as the force of the pull act about the same point, however, this just seems like that it would take to tip the ladder backwards, not make it slide. I am not really sure where to go from here.
Homework Equations
(sum of forces in x dir) : Force of pull - force of static friction = 0
(sum of forces in y dir) : -20 + normal force at A = 0
(sum of moments about A) : -20lb(5.3m)-force of pull(5.3m) = 0
The Attempt at a Solution
Force of pull= 20lb. Now i think the number worked out this was just cause the angle is 45 degrees and gravity as well as the force of the pull act about the same point, however, this just seems like that it would take to tip the ladder backwards, not make it slide. I am not really sure where to go from here.