- #1
mesa
Gold Member
- 695
- 38
I want to make sure I understand the relationship between OH- and COOH properly.
So if the NaOH is introduced into a buffer solution of acetic acid and it dissociates does the OH- (due to it's very electronegative nature) immediately rip off the H+ from the COOH? If I want to calculate pH do I just subtract the mols of NaOH from mols CH3COOH then calculate the pH from the remaining acetic acid (in molarity) and it's corresponding Ka (1.75X10^(-5))?
So if the NaOH is introduced into a buffer solution of acetic acid and it dissociates does the OH- (due to it's very electronegative nature) immediately rip off the H+ from the COOH? If I want to calculate pH do I just subtract the mols of NaOH from mols CH3COOH then calculate the pH from the remaining acetic acid (in molarity) and it's corresponding Ka (1.75X10^(-5))?