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Ace.
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1. Prove:[tex]\frac{cscx +cotx}{cscx-cotx} = \frac{1+2cosx+cos^2x}{sin^2x}[/tex]
tanx = [itex]\frac{sinx}{cosx}[/itex]
cotx = [itex]\frac{cosx}{sinx}[/itex]
cscx
secx
cotx
[itex]sin^2x + cos^2x = 1[/itex]
Left side:
=[itex]\frac{cscx +cotx}{cscx-cotx}[/itex]
=[itex]\frac{1/sinx + cosx / sinx}{1/sinx - cosx/sinx}[/itex]
=[itex]\frac{1+cosx}{1-cosx}[/itex]
Homework Equations
tanx = [itex]\frac{sinx}{cosx}[/itex]
cotx = [itex]\frac{cosx}{sinx}[/itex]
cscx
secx
cotx
[itex]sin^2x + cos^2x = 1[/itex]
The Attempt at a Solution
Left side:
=[itex]\frac{cscx +cotx}{cscx-cotx}[/itex]
=[itex]\frac{1/sinx + cosx / sinx}{1/sinx - cosx/sinx}[/itex]
=[itex]\frac{1+cosx}{1-cosx}[/itex]
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