- #1
SpatialVacancy
- 24
- 0
Hello all,
Prove that [tex] \sqrt[3]{3} [/tex] is irrational.
Heres what I have so far:
[tex] \sqrt[3]{3}=\dfrac{m}{n}[/tex]
[tex]3=\dfrac{m^3}{n^3}[/tex]
[tex]m^3=3n^3 [/tex]
Now, I think I am to assume that there is more than one factor of three on the right, or something, I don't know. Can someone point me in the right direction?
Thanks.
Prove that [tex] \sqrt[3]{3} [/tex] is irrational.
Heres what I have so far:
[tex] \sqrt[3]{3}=\dfrac{m}{n}[/tex]
[tex]3=\dfrac{m^3}{n^3}[/tex]
[tex]m^3=3n^3 [/tex]
Now, I think I am to assume that there is more than one factor of three on the right, or something, I don't know. Can someone point me in the right direction?
Thanks.