- Thread starter
- #1

#### Petrus

##### Well-known member

- Feb 21, 2013

- 739

I am working with old exam and got one problem that gives 5 points (total 30 points) and it says

line \(\displaystyle l_1\) and \(\displaystyle l_2\) gives of

\(\displaystyle (x,y,z)=(1,0,1)+t(2,3,0)\) and \(\displaystyle (x,y,z)=(2,0,-2)+t(1,2,1)\)

prove that \(\displaystyle l_1\) and \(\displaystyle l_2\) intersect each other.

this is how I solved:

There is an intersect only if this equation got a solution:

\(\displaystyle 1+2t=2+s\)

\(\displaystyle 3t=2s\)

\(\displaystyle 1=-2+s\)

from equation 3 we get that \(\displaystyle s=3\) and if we put \(\displaystyle s=3\) in equation 2 we get that \(\displaystyle t=2\) and if we put all those in equation we see it's true.

Well do you think this is good explain? It's pretty much 5 points that is alot and that's why I wanna ask for advice if this would be enough for 5 points acording to you

Regards,

\(\displaystyle |\pi\rangle\)