Prove that the interval A = [0 , 2) has the same cardinality as the set B = [5 , 6) U [7 , 8)

[KOO]

Prove that the interval A = [0 , 2) has the same cardinality as the set B = [5 , 6) U [7 , 8) by constructing a bijection between the two sets

Attempt:

x ↦ x + 5 for x ∈ [0 ; 1)
x ↦ x + 6 for x ∈ [1 ; 2)

What to do next?

 

[Fernando Revilla]

What to do next?

Prove that $f:[0,2)\to [5\color{red},\color{\black}6)\cup [7,8)$
$$f(x)=\left \{ \begin{matrix} x+5& \mbox{ if }& x\in [0,1)\\x+6 & \mbox{ if }&x\in [1\color{red},\color{\black}2)\end{matrix}\right.$$
is injective and surjective.

 

[KOO]

Prove that $f:[0,2)\to [5.6)\cup [7,8)$
$$f(x)=\left \{ \begin{matrix} x+5& \mbox{ if }& x\in [0,1)\\x+6 & \mbox{ if }&x\in [1.2)\end{matrix}\right.$$
is injective and surjective.

Did you mean [5,6) and not [5.6)?

Also, [1,2) and not [1.2)?

Thanks!

 

[Fernando Revilla]

Did you mean [5,6) and not [5.6)?
Also, [1,2) and not [1.2)?

Of course, my fingers were clumsy.