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- Feb 14, 2012
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Let $PQRS$ be a rhombus with $\angle Q=60^{\circ}$. $M$ is a point inside triangle $PSR$ such that $\angle PMR=120^{\circ}$. Let lines $QP$ and $RM$ intersect at $A$ and lines $QR$ and $PM$ intersect at $B$. Prove that $S$ lies on the line $AB$.