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maxkor
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Let BCED and ACFG square. Prove that center of DG = center of the red circle.
View attachment 6025
I don't know how to start
View attachment 6025
I don't know how to start
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Extend some of the lines in the figure.maxkor said:
To prove that the center of a DG (diameter) is equal to the center of a red circle, we can use the fact that the center of a circle is equidistant from all points on its circumference. This means that if we draw a line from the center of the DG to any point on the circumference of the red circle, it should be the same length as a line drawn from the center of the red circle to the same point on its circumference.
The main evidence that supports this claim is the definition of a circle, which states that all points on the circumference are equidistant from the center. We can also use the Pythagorean theorem to calculate the distance between the centers of the two circles, and show that it is equal to the radius of each circle.
Yes, we can provide a visual representation by drawing a diagram of the two circles and connecting their centers with a line segment. We can then label the radius of each circle and show that they are equal in length. This visually demonstrates that the centers of the two circles are in fact the same point.
The main assumption made in this proof is that the two circles are perfect and symmetrical, meaning that the center of each circle is the exact same point. We also assume that the definition of a circle applies, which states that all points on the circumference are equidistant from the center.
This proof is applicable to all circles, as it relies on the fundamental definition of a circle. As long as the two circles have a defined center and are perfect and symmetrical, this proof can be used to show that their centers are equal.