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#### karush

##### Well-known member

\begin{align*}\displaystyle

\frac{\tan^2 t -1}{\sec^2 t}

&=\frac{\tan t-\cot t}{\tan t+\cot t}\\

\frac{\tan^2 t -1}{\tan^2 t+1}&=

\end{align*}

OK I continued but I could not derive an equal identity

I saw a solution to this on SYM but it was many steps and got very bloated

there must be some way to do this in like 3 steps?