- Thread starter
- #1
Albert
Well-known member
- Jan 25, 2013
- 1,225
A=$1001^{999}$
B=$1000^{1000}$
Prove :A<B
(note :any calculation tools are not allowed ,also no use of log function)
B=$1000^{1000}$
Prove :A<B
(note :any calculation tools are not allowed ,also no use of log function)