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- Thread starter Yankel
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- Mar 10, 2012

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Seems correct to me.Hello, I wanted to ask if this is a correct move, A and B are matrices, a is a scalar, thank you !

[tex]A^{2}\cdot B^{t}-aA=A(A\cdot B^{t}-aI)[/tex]

- Feb 5, 2012

- 1,621

Hi Yankel,Hello, I wanted to ask if this is a correct move, A and B are matrices, a is a scalar, thank you !

[tex]A^{2}\cdot B^{t}-aA=A(A\cdot B^{t}-aI)[/tex]

Yes, its correct because matrix multiplication is distributive over matrix addition.

Kind Regards,

Sudharaka.

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