- #1
rootoftwo
- 1
- 0
Hello, this may be a rather simple question but it's beginning to irritate me: If I were launching a marble of, say, 10g (0.010 kg) from a marble launcher with a force of 5N (tell me if this is realistic or not) at an angle of 15 degrees then how would I go about finding the initial velocity of the marble?
Please tell me if I was taking to this question in the correct manner:
I first split the force F into it's horizontal and vertical components:
Fx=5*cos15
Fx=4.83
Fy=5*sin15
Fy=1.29
I then found, using F= m * a, the initial horizontal and vertical acceleration:
Ax = 483
Ay = 129
This is the point I was truly having trouble with, finding the initial vertical and horizontal velocities:
To do this, I assumed that since the initial velocity are found at the moment all of the force is transferred to the marble:
Vx = Ax
Vy = Ay
Is this true?
Please tell me if I was taking to this question in the correct manner:
I first split the force F into it's horizontal and vertical components:
Fx=5*cos15
Fx=4.83
Fy=5*sin15
Fy=1.29
I then found, using F= m * a, the initial horizontal and vertical acceleration:
Ax = 483
Ay = 129
This is the point I was truly having trouble with, finding the initial vertical and horizontal velocities:
To do this, I assumed that since the initial velocity are found at the moment all of the force is transferred to the marble:
Vx = Ax
Vy = Ay
Is this true?