Projectile Motion Problem Help

[gabbiem10]

I am in an Honors Physics I class at my school and we are just starting to learn about projectile motion. I am having a bit of trouble with some homework and am in need of help.

Problems:
1. I kick a rock horizontally off a ledge that is 20 m high. Once in the air, the rock is in free-fall. How far forward does the rock travel before hitting the ground?
A: I used ΔY=1/2(a)(Δt)^2 to solve for Δt if ΔY = 20m V_y,i = 0 m/s and
a = -9.8 m/s². I got Δt ≈ 2.0s. Is it even possible to solve this with the given information?

2. A long-jumper leaves the ground with an initial velocity of 12 m/s at an angle of 28 degrees above the horizontal. Determine the long-jumper's time of flight.
I solved for the y component using V_y,i = Rsinθ and
V_x = Rcosθ. V_y,i = 5.6 m/s and V_x = 10.6 m/s. a = -9.8 m/s^2 but that was as far as I could get with the given information.

 

[azizlwl]

I am in an Honors Physics I class at my school and we are just starting to learn about projectile motion. I am having a bit of trouble with some homework and am in need of help.

Problems:
1. I kick a rock horizontally off a ledge that is 20 m high. Once in the air, the rock is in free-fall. How far forward does the rock travel before hitting the ground?
A: I used ΔY=1/2(a)(Δt)^2 to solve for Δt if ΔY = 20m V_y,i = 0 m/s and
a = -9.8 m/s². I got Δt ≈ 2.0s. Is it even possible to solve this with the given information?

2. A long-jumper leaves the ground with an initial velocity of 12 m/s at an angle of 28 degrees above the horizontal. Determine the long-jumper's time of flight.
I solved for the y component using V_y,i = Rsinθ and
V_x = Rcosθ. V_y,i = 5.6 m/s and V_x = 10.6 m/s. a = -9.8 m/s^2 but that was as far as I could get with the given information.

1. Just a nudge, it won't go far forward. Forward depends on initial horizontal velocity.
2. Hidden data. Vertical displacement =0

 

[gabbiem10]

1. Just a nudge, it won't go far forward. Forward depends on initial horizontal velocity.

The problem is that the initial horizontal velocity is not given neither is the horizontal displacement. The time was calulated base upon other given factors.