- #1
btb4198
- 572
- 10
I need an equation to give me the backspin speed in HZ and the torque applied to motor from back spin from a given oil well.
The VFD given me the rod torque during forward run. J = 706 lbs-ft. J = F * D
D= 7300 ft = Length of the rod
J = Jm - Jf -Jb +Jten
so I am not sure how to do this ...
can someone help ?
Jten = torque of tension
Jm = torque of the force from the oil
Jb = torque from the backspin hydro brake in the drive head
Jf = torque from the friction on the pcp case
F=MA
M = F/A
M = F/(32.174 ft/s^2)
F = Jf/D
Jm = J + Jb -Jten + Jf
Jb is given in the wellhead doc
but I still need to find t (time)
So, I can get speed of the backspin
I am not too sure
does anyone know ?
The VFD given me the rod torque during forward run. J = 706 lbs-ft. J = F * D
D= 7300 ft = Length of the rod
J = Jm - Jf -Jb +Jten
so I am not sure how to do this ...
can someone help ?
Jten = torque of tension
Jm = torque of the force from the oil
Jb = torque from the backspin hydro brake in the drive head
Jf = torque from the friction on the pcp case
F=MA
M = F/A
M = F/(32.174 ft/s^2)
F = Jf/D
Jm = J + Jb -Jten + Jf
Jb is given in the wellhead doc
but I still need to find t (time)
So, I can get speed of the backspin
I am not too sure
does anyone know ?
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