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I have a problem on how to generalize this sequence.

Problem:

In sequence a,b,x1,x2,.....xn,...,each term is equals to the arithmetic mean of its two preceding numbers.Using a and b, find:

1.xn

2.lim(n->∞) xn

My working:

x

x

Ok, so I did the same thing as above until x

(a+b)/2,(a+3b)/4,(3a+5b)/8,(5a+11b)/16,(11a+21b)/32+.........

I realize a pattern here. Obviously, the denominator is just increasing by 2n. I see a pattern in the numerator too,but it's hard to generalize it using n.I realize that the value of the second a is equals to the value of the previous b and the value of the third a is equals to the second b and it goes on.

You see it too,don't you?When the first term has b in the numerator,then the second term has a, and when the 2nd term has 3b in the numerator, the 3rd term has 3a and so on...now we just have to generalize that,don't we?

Problem:

In sequence a,b,x1,x2,.....xn,...,each term is equals to the arithmetic mean of its two preceding numbers.Using a and b, find:

1.xn

2.lim(n->∞) xn

My working:

x

_{1}= (a+b)/2, x_{2}=(b+x_{1})/2x

_{3}= (x_{2}+x_{1})/2....Ok, so I did the same thing as above until x

_{5}and substituted all that are needed to be substituted with a and b.And here's what I get:(a+b)/2,(a+3b)/4,(3a+5b)/8,(5a+11b)/16,(11a+21b)/32+.........

I realize a pattern here. Obviously, the denominator is just increasing by 2n. I see a pattern in the numerator too,but it's hard to generalize it using n.I realize that the value of the second a is equals to the value of the previous b and the value of the third a is equals to the second b and it goes on.

You see it too,don't you?When the first term has b in the numerator,then the second term has a, and when the 2nd term has 3b in the numerator, the 3rd term has 3a and so on...now we just have to generalize that,don't we?

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