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- #1

$$

pr(X=k)=\mu\frac{\prod^{k-1}_{i=1}\{1-\mu+(i-1)\theta\}}{\prod^{k}_{i=1}\{1+(i-1)\theta\}}, \quad \mbox{for k$\geq$ 1,}

$$

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- Thread starter
- #1

$$

pr(X=k)=\mu\frac{\prod^{k-1}_{i=1}\{1-\mu+(i-1)\theta\}}{\prod^{k}_{i=1}\{1+(i-1)\theta\}}, \quad \mbox{for k$\geq$ 1,}

$$

type \displaystyle in front of \prod

$$

pr(X=k)=\mu\frac{\prod^{k-1}_{i=1}\{1-\mu+(i-1)\theta\}}{\prod^{k}_{i=1}\{1+(i-1)\theta\}}, \quad \mbox{for k$\geq$ 1,}

$$

$$

pr(X=k)=\mu\frac{\displaystyle\prod^{k-1}_{i=1}\{1-\mu+(i-1)\theta\}}{\displaystyle\prod^{k}_{i=1}\{1+(i-1)\theta\}}, \quad \mbox{for k$\geq$ 1,}$$

- Jan 30, 2012

- 2,488

See also p. 144 of

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