What is the power input to the plant?

The conversation discusses calculating efficiency and power output for a power plant operating at specific temperatures and with a specific output. It also includes questions about the amount of water needed to carry away heat and the amount of coal needed to supply the plant. Another conversation topic involves an electron moving between charged parallel plates, and questions about its initial velocity, the electric and magnetic fields, and the acceleration between the plates. In summary, the conversation covers topics related to power plant efficiency, power output, and electric and magnetic fields for an electron moving between charged plates.
  • #1
JM2107
I have a few questions that i need help understanding how to answer:

1. At a power plant, the operating temperatures are 700 C and 310 C. The efficiency of the plant is 65% of its Carnot efficiency. The output of the plant is 500 MW.
a. Determine the efficiency of the plant.
b. What is the power input to the plant?
c. The heat released by the plant is carried away by water. How many kg/sec must pass through the
plant if the maximum allowed temperature increase is 20C?
d. The heat of combustion of coal is 2.8 x 109 J/kg. How many kg of coal must be burned per hour to
supply the plant?


2. An electron initially moves in a horizontal direction midway between two charged parallel plates with a kinetic energy of 2000 eV. The plate separation d = 0.02 m and the length of the plates L=0.040m. The potential difference between the plates is 250 volts.
a. Determine the initial velocity, v, in the position shown.
b. What are the magnitude and direction of the electric field between the
plates?
c. What are the magnitude and direction of the acceleration of the electron
between the plates.
d. What are the magnitude and direction of a magnetic field that, if applied
between the plates, would cause the electron to travel in a straight line?



For the first problem, I have determined that the efficiency of the engine is 26.1%. I can't figure out how to solve question 1b and the rest of the problem. I also don't know how to do problem number 2. Any help that is provided will be greatly appreciated, I need to know how to correctly solve these two problems before my final.
 
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  • #2
No HW!

We don't do your homework in this forum but rather we discuss any ideas and questions. Problems are welcome but don't give us your homework...
 
  • #3
Forum rules state that for us to help you'll need to at least try the problem and show us where you got stuck.

It doesn't help you if we do your homework for you.
 
  • #4
JM,

I deleted your other thread, because it was identical to this one. As the others said, tell us your thoughts on the problems and we will help you through your difficulties.
 
  • #5
JM,

I'd love to help with #1 but they're all going to jump on me if I give it away too easily, so you have to try harder.

I'll tell you this:
I agree with your answer to part a, so you seem to have the basic idea.

Now, forget about applying a formula and ask yourself, exactly what does efficiency mean?
 
  • #6
Sorry about the Misinterpretation

I was not asking if someone could do the homework for me, I was simply just asking if someone could explain to me how i should go about solving the problems. I have used these forums before and never once asked for someone to "do my homework for me". I just felt that if I were to put the entire question in the post that I would be giving the person that helped me a full sense of what I was working on. In the earlier post it may have appeared that what I was asking for was for someone to do my HW for me but I am aware that this isn't the purpose of these forums. All I would like to know is what steps I should follow to answewr question 1b.
 
  • #7
Originally posted by JM2107
For the first problem, I have determined that the efficiency of the engine is 26.1%.

How did you get that? I got about 36%.

This is what I mean by "show me your work". That way, I can point your mistake out to you, instead of posting my solution.

I can't figure out how to solve question 1b and the rest of the problem.

Once you get part 1a, this should be dead easy. The efficiency is the power output divided by the power input.
 
  • #8


Originally posted by Tom
How did you get that? I got about 36%.

And, of course, I forgot to convert to Kelvin, like a dumbass. 26% is correct.
 
  • #9
Tom:

JM's answer of 26.1% for part a is correct.
The Carnot efficiency EC = 1 - Tc/Th
= 1 - 583K/973K = 40.1%

It is given that the engine's efficiency is 65% of that:
40.1% * 65% = 26.1%


JM:

The next step is to use the general definition of efficiency which (as Tom pointed out) is
E = output/input (expressed either in terms of energy or power)

see if you can make any progress with that...
 

1. What is the definition of power input to the plant?

The power input to the plant refers to the amount of energy that is supplied to the plant in order for it to perform its functions, such as growth and metabolism.

2. How is the power input measured in a plant?

The power input to a plant can be measured in units of energy, such as joules or kilojoules, or in units of power, such as watts. It can also be measured by monitoring the amount of light, water, and nutrients that the plant receives.

3. What factors affect the power input to a plant?

The power input to a plant can be affected by various factors, including the intensity and duration of light exposure, the availability of nutrients, the quality and quantity of water, and the environmental conditions such as temperature and humidity.

4. Why is it important to understand the power input to a plant?

Understanding the power input to a plant is important because it helps us understand how much energy the plant is receiving and how efficiently it is using that energy. This information can be used to optimize plant growth and health, as well as to inform agricultural practices.

5. How can the power input to a plant be manipulated?

The power input to a plant can be manipulated by adjusting the amount of light, water, and nutrients it receives. For example, increasing the amount of light or nutrients can result in an increase in power input and potentially improve plant growth. However, it is important to note that manipulating the power input must be done carefully and in accordance with the specific needs of the plant.

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