- #1
SwedishFred
- 28
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Hi
A rod comprises a counterweight (a) a handle and a hook which hangs mass (m), the rods mass is 400g counterweight mass (a) = 1600g and the rod is 0.8m long. Equilibrium exists when the handle is at position X = 12.0cm
How I did
1: calculated the length of the handle to (m) which was 0.68m
2: figured kg from 1.6 kg * 0.12 = 0.192 kg
3 0.192 = 0.68*m
but how do you do with the rod weighs 400g how do I calculate it??
The question is to calculate the total mass of (m) to obtain equilibrium
hope you understand the language and metrics, used google translate, did work out that great, but I´m loosing time
regards fredrik
A rod comprises a counterweight (a) a handle and a hook which hangs mass (m), the rods mass is 400g counterweight mass (a) = 1600g and the rod is 0.8m long. Equilibrium exists when the handle is at position X = 12.0cm
How I did
1: calculated the length of the handle to (m) which was 0.68m
2: figured kg from 1.6 kg * 0.12 = 0.192 kg
3 0.192 = 0.68*m
but how do you do with the rod weighs 400g how do I calculate it??
The question is to calculate the total mass of (m) to obtain equilibrium
hope you understand the language and metrics, used google translate, did work out that great, but I´m loosing time
regards fredrik