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- Jan 26, 2012

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\(\displaystyle \sum_{i=1}^{10}\frac{2i+1}{i^2(i+1)^2}\)

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- Thread starter
- Admin
- #1

- Jan 26, 2012

- 4,055

\(\displaystyle \sum_{i=1}^{10}\frac{2i+1}{i^2(i+1)^2}\)

--------------------

Remember to read the POTW submission guidelines to find out how to submit your answers!

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- Jan 26, 2012

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1) hxthanh

2) Chris L T521

3) MarkFL

4) eddybob123

5) johng

6) anemone

Solution (from hxthanh):

With $n=10$, we get: $S_{10}=1-\dfrac{1}{121}=\boxed{\dfrac{120}{121}}$

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