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- #1
- Jan 26, 2012
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Thank you to MarkFL for proposing this problem for us to use![HR][/HR]
Using the triple-angle identity for cosine:
(1) $\displaystyle \cos(3\theta)=4\cos^3(\theta)-3\cos(\theta)$
solve the cubic equation:
(2) $\displaystyle 8x^3-6x-1=0$
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Remember to read the POTW submission guidelines to find out how to submit your answers!
Using the triple-angle identity for cosine:
(1) $\displaystyle \cos(3\theta)=4\cos^3(\theta)-3\cos(\theta)$
solve the cubic equation:
(2) $\displaystyle 8x^3-6x-1=0$
--------------------
Remember to read the POTW submission guidelines to find out how to submit your answers!