- Thread starter
- Admin
- #1

- Jan 26, 2012

- 4,041

--------------------

Remember to read the POTW submission guidelines to find out how to submit your answers!

- Thread starter Jameson
- Start date

- Status
- Not open for further replies.

- Thread starter
- Admin
- #1

- Jan 26, 2012

- 4,041

--------------------

Remember to read the POTW submission guidelines to find out how to submit your answers!

- Thread starter
- Admin
- #2

- Jan 26, 2012

- 4,041

1) MarkFL

2) anemone

3) Sudharaka

Solution (from Sudharaka):

\[L_1:\, (x,\,y,\,z)=(4,\,3,\,-2)+t(3,\,-4,\,-1)\]

Since \((m,\,n,\,-5)\) is on \(L_1\) we have,

\[L_1:\, (m,\,n,\,-5)=(4,\,3,\,-2)+t(3,\,-4,\,-1)\]

\[\Rightarrow t=3\]

\[\therefore m=4+3t=13\mbox{ and }n=3-4t=-9\]

- Status
- Not open for further replies.