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- Jan 26, 2012

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Remember to read the POTW submission guidelines to find out how to submit your answers!

- Thread starter Jameson
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- Thread starter
- Admin
- #1

- Jan 26, 2012

- 4,055

--------------------

Remember to read the POTW submission guidelines to find out how to submit your answers!

- Thread starter
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- #2

- Jan 26, 2012

- 4,055

1) MarkFL

2) anemone

3) Sudharaka

4) Reckoner

Solution (from MarkFL):

$\displaystyle C(10)=\frac{G}{10}$

Now, when $n$ additional contributors are added from an original 10 contributors, we find:

$\displaystyle \Delta C=C(10+n)-C(10)=\frac{G}{10+n}-\frac{G}{10}=G\left(\frac{1}{10+n}-\frac{1}{10} \right)=-\frac{Gn}{10(10+n)}$

Hence, we find the decrease in the contribution required from each person is:

$\displaystyle \frac{Gn}{10(10+n)}$

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