# Problem Of The Week #435 September 21st, 2020

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#### anemone

##### MHB POTW Director
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No one answered last week's POTW.

However, I have decided to give the community another week to attempt at the problem.

#### anemone

##### MHB POTW Director
Staff member
Congratulations to Opalg for his correct solution , which you can find below:

If $f(x) = x^4-8x^3+24x^2+bx+c$ has four real roots then its derivative must have three real roots. But $$f'(x) = 4x^3 - 24 x^2 + 48x + b = 4(x-2)^3 + b + 32,$$ and the function $(x-2)^3$ is strictly increasing except at the point $x=2$. So $f'(x)$ can only have three real roots if $b+32 = 0$. Therefore $b = -32$.

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