- Thread starter
- Admin
- #1

- Jan 26, 2012

- 4,055

Thanks to Chris L T521 for helping with this one.

If $n$ is a positive integer, show that \(\displaystyle {n\choose 0} + {n\choose 1} + \cdots + {n\choose n} = 2^n\)

Hint:

Remember to read the POTW submission guidelines to find out how to submit your answers!

If $n$ is a positive integer, show that \(\displaystyle {n\choose 0} + {n\choose 1} + \cdots + {n\choose n} = 2^n\)

Hint:

Rewrite $2^n$

Remember to read the POTW submission guidelines to find out how to submit your answers!

Last edited: