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- Jan 26, 2012

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- Thread starter
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- #1

- Jan 26, 2012

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Remember to read the POTW submission guidelines to find out how to submit your answers!

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- Jan 26, 2012

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1) Sudharaka

2) Reckoner

Solution (from Sudharaka):

The wheel travels a distance equal to it's circumference in one revolution. Since \(d\) feet is covered in \(100\) revolutions,

\[d=100\pi x\]

Let \(r\) be the number of revolutions that the second wheel make when covering \(d\) feet. Then,

\[d=100\pi x=r\pi y\]

\[\therefore r=\frac{100 x}{y}\]

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