Can the Integral of csc2 be Simplified Using the Tabular Method?

  • Thread starter himanshu121
  • Start date
  • Tags
    Integral
In summary, the problem is to find the integral of x^2*(cscx)^2 from 1 to pi. The straightforward way is probably the easiest, but it's not the shortest way. There are many ways of doing the problem, but the shortest way is not easy to find.
  • #1
himanshu121
653
1
Here is the Problem:

[tex] \int_0^\pi\theta^2cosec^2\theta d\theta[/tex]


I want to do this problem by parts and finding hard to find shortest way to do the problem any shortest way pls
 
Last edited:
Physics news on Phys.org
  • #2
The straightforward way is probably the easiest. integral of csc2 is -ctn and integral of ctn is log(sin). Integrating log(sin) may take a little work.
 
  • #3


Originally posted by himanshu121
Here is the Problem:

[tex] \int_0^\pi\theta^2cosec^2\theta d\theta[/tex]


I want to do this problem by parts and finding hard to find shortest way to do the problem any shortest way pls

cos*sec^2(x) or cosx*sec^2(x)?
 
  • #4


Originally posted by PrudensOptimus
cos*sec^2(x) or cosx*sec^2(x)?
Isn't it csc(x)?
 
  • #5
It is cosecant(x) i.e csc(x)
Integrating log(sin) may take a little work

This is probably the easiest way of doing which i too have tried but it is not the shortest way

There are many ways of doing a problem i am looking for shortest way
Thnxs
 
  • #6
How about:

[tex]
\begin{align*}
\int_0^\pi\theta^2\csc^2\theta\;d\theta
&=\int_0^1\theta^2\csc^2\theta\;d\theta+\int_1^\pi\theta^2\csc^2\theta\;d\theta \\
&>\int_0^1\theta^2\csc^2\theta\;d\theta+\int_1^\pi\csc^2\theta\;d\theta \\
&=\int_0^1\theta^2\csc^2\theta\;d\theta+\left[-\cot\theta\right]_1^\pi
\end{align*}
[/tex]

Now since [itex]\lim\limits_{\theta\rightarrow\pi}(-\cot\theta)=+\infty[/itex] we know that the rightmost term diverges. Moreover, the left integral (the one from 0 to 1) is clearly positive. Thus the original integral clearly diverges.
 
  • #7
master_coda:
the integral of x^2*(cscx)^2 from 1 to pi comes out to be about 4.2
the integral of (cscx)^2 from 1 to pi goes to inifinite. I believe to say the integral of x^2*(cscx)^2 from 1 to pi is greater than the integral of (cscx)^2 from 1 to pi since according to the values it came out as then the formula should be switched around and divergence would not be proved.

himanshu121:
Best way to do it would be to plug it into a calculator or look it up in a table. Otherwise you're probably stuck with integrating log(sin(x)).

jk
 
Last edited:
  • #8
Best way to do it would be to plug it into a calculator or look it up in a table

We are not allowed to use calculator in India till we are undergraduate
I found the way but don't know whether it is shortest one or not but definately i won't stuck at log(sinx)



[tex]

I = \int_0^\pi\theta^2\csc^2\theta d\theta [/tex]

[tex]I= \int_0^\pi\ (\pi-\theta)^2\csc^2\theta d\theta [/tex]

this gives

[tex] \pi\int_0^\pi\csc^2 \theta d\theta = 2\int_0^\pi\theta\csc^2\theta d\theta [/tex]

integrating by parts with one part as [tex]\theta[/tex] and other as [tex]\theta\csc^2\theta d\theta [/tex]

i will get[tex] \int_0^\pi \cot\theta d\theta = \log(csc\theta-cot\theta)
[/tex]

much easier than integrating log(sinx)

But another problem is how i will put the limits in cotx from 0 to pi in both cases it is infinity and i know there is no break in the function cotx b/w these points
 
Last edited:
  • #9
I agree with master_coda...

the integral of x^2*(cscx)^2 from 1 to pi comes out to be about 4.2

Where did you come up with this?! My calculator says 3*10^14 with the caveat of "questionable accuracy" (though, 3*10^14 is a good approximation of infinity. :wink:)
 
  • #10
Originally posted by Hurkyl
(though, 3*10^14 is a good approximation of infinity. :wink:)
Yes, for large values of 3*10^14.

- Warren
 
  • #11
I'm pretty sure that the integral diverges. My algebra, my calculator and my computer all agree.

Also, if it's any help, [itex]\csc\theta-\cot\theta=\frac{1-\cos\theta}{\sin\theta}[/itex].
 
  • #12
hurkyl. yeah that 4.2 was kinda off huh? just keeping you on your toes i guess:P i entered it in wrong but i redid it and came up with what you got.

i used u=(x^2)csc^2(x) and dv=dx and came up with the first term (x^3*csc^2(x)) going to infinite so i think you might be right coda.

jk
 
Last edited:
  • #13
Why don't you try using the tabular method to doing this problem.
Since theta^2 will eventually go to zero if you keep on taking the derivatives, you should do it by tabular method
 

1. What is the integral of csc²?

The integral of csc² is equal to -ctn.

2. How do you solve for the integral of csc²?

To solve for the integral of csc², you can use the trigonometric identity csc²(x) = 1 + cot²(x) and then apply the power rule for integration.

3. Can the integral of csc² be simplified?

Yes, the integral of csc² can be simplified using the trigonometric identity csc²(x) = 1 + cot²(x) and then applying the power rule for integration.

4. Is there a specific range for the integral of csc²?

The integral of csc² does not have a specific range, as the function is defined for all real numbers except for multiples of pi.

5. How is the integral of csc² used in real-world applications?

The integral of csc² has various applications in physics, engineering, and mathematics. It is used to solve problems involving periodic motion, such as calculating the work done by a pendulum or the displacement of a spring. It is also used in signal processing and in the study of electromagnetic waves.

Similar threads

Replies
2
Views
181
  • Calculus
Replies
29
Views
521
Replies
3
Views
939
Replies
8
Views
311
Replies
4
Views
193
Replies
16
Views
1K
Replies
2
Views
2K
Replies
3
Views
535
Replies
33
Views
3K
Replies
1
Views
833
Back
Top