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Problem of the week #27 - October 1st, 2012

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Jameson

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Jan 26, 2012
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6 pints of a 20 percent solution of alcohol in water are mixed with 4 pints of a 10 percent alcohol in water solution. The percentage alcohol in the new solution is ___________?
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Jameson

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Jan 26, 2012
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Congratulations to the following members for their correct solutions:

1) Reckoner
2) Sudharaka

Solution (from Sudharaka):

The number of pints of alcohol in the first solution \(\displaystyle=6\times\frac{20}{100}=\frac{6}{5} \)


The number of pints of alcohol in the second solution \(\displaystyle=4\times\frac{10}{100}=\frac{2}{5} \)


The percentage of alcohol in the new solution \(\displaystyle=\frac{\frac{6}{5}+\frac{2}{5}}{10}\times 100=\frac{8}{5}\times 10=16\%\)
 
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