Solving Algebra of Functions: f(500)=3, f(600)?

In summary, the conversation discusses the function f(x) and its value at different points. It is stated that the value of f(500) is 3, but the value of f(600) is unknown without more information about the function. The conversation also mentions that the function cannot be solved or graphed without additional information. A real-life example of this type of equation could be a situation where the value of a quantity at one point is known, but the value at another point needs to be determined through further information or calculations.
  • #1
Moose352
166
0
I'm not too confident with problems dealing with the algebra of functions. For example, how would you approach this problem:

Function f satisfies: f(xy) = f(x)/y
If f(500) = 3, what is f(600)?

Thanks
 
Last edited:
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  • #2
[tex]f(xy)=\frac{f(x)}{y}[/tex]
Now, if
[tex]xy=500[/tex] and [tex]x=600[/tex]
can you figure out what [tex]y[/tex] is?
 
  • #3
600=500*(6/5)
 
  • #4
Ah! Simple enough. Thanks a bunch.
 

1. What is the value of f(500)?

The value of f(500) is equal to 3.

2. What is the value of f(600)?

The value of f(600) has not been specified and cannot be determined without more information about the function.

3. How do you solve for f(x) in this equation?

We cannot solve for f(x) without knowing the specific function. The given information only tells us the value of f(500) and does not provide enough information to solve for f(x).

4. Can this equation be graphed?

No, this equation cannot be graphed without more information about the function.

5. Can you provide a real-life example of this type of equation?

Yes, this type of equation can represent a situation where a quantity, represented by f(x), has a specific value at a certain point, in this case f(500) = 3, and the value at another point, f(600), is unknown and needs to be determined through additional information or calculations.

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