Problem in Geometric Probability

In summary, the normal algebric probability is easy to understand but I find the geometric probabilities less understandable. Can you please help me with a few problem related to this area of probability so that I can understand it better. Here are my problems, 1. Two persons A and B agree to meet at a place between 11 to 12 noon . The first one to arrive waits for 20 min and then leaves. If the time of their arrival be independent and at random, what is the probability that A and b meet?(Ans :5/9)2.Consider the cartesian plane R^2 and let X denote the subset of points for which both co-ordinates are integers, A coin of diameter 1/
  • #1
Arka
4
0
The normal algebric probability is easy to understand but I find the geometric probabilities less understandable. Can you please help me with a few problem related to this area of probability so that I can understand it better. Here are my problems,
1. Two persons A and B agree to meet at a place between 11 to 12 noon . The first one to arrive waits for 20 min and then leaves. If the time of their arrival be independent and at random, what is the probability that A and b meet?(Ans :5/9)

2.Consider the cartesian plane R^2 and let X denote the subset of points for which both co-ordinates are integers, A coin of diameter 1/2 is tossed randomly onto the plane. Find the probability that the coin covers a point of X.(Ans: 0.2(approx))

Please give me detailed stepwise solution to the two problems with explanation for the steps. Thanks.:smile:
 
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  • #2
By the way it's not some homework problem. The problem was given in a math olympiad in my country.They say that these sums are quite easy but I can't even understand how to proceed with the first step.It's not like those normal probability sums I have encountered before. Please give me some ideas to solve them.
 
  • #3
I assume in problem one , that the 2nd person just arrived at some point and left, without waiting, and arrived at 11:40 at the latest (since 11:40+20 min =12:00)? Could we also assume the 1st person stayed for 20 minutes, did not meet the 1st and then left? Sorry, maybe it is obvious.

And, sorry, but it is against the policy of this site to give out explicit, detailed answers, even if it is not HW, but we will do our best to guide you through to the answer.
 
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  • #4
For the 2nd, I would do something like this: consider a single square with vertices in ## \mathbb N \times \mathbb N ##. What region around any of the vertices would be a "winning region", i.e., a region where a coin falling would intersect the vertices?

For the 1st, I would suggest you consider the relation ##|A_1-A_2| \leq 20 ## , where ##A_1, A_2## are the arrival times, within a ## 60 \times 60 ## square, or one going from 12 to 1..
 
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  • #5
Can you explain the graphical representation of these two sums. Thats what I'm not getting. The detailed solution won't matter as long as I understand the graph.Thanks.
 
  • #6
Sorry I don't have too much time to go into detail, but I will come back later. The coin falls any where in the plane with equal probability . Note that I am making some simplifying assumptions and my work may not hold if these assumptions are false. The idea is that the corner of the coin farthest from a pair of the integers must land within a region that is 1/4 units (radius of coin) or less away from the pair of integers for the coin to overlap this pair of points. Notice this is not physically realistic, in that the coin may flip up-and-down before settling, but again, this is a Math problem ( I assume) and not a Physics problem, so I assume if the point in the coin farthest from the vertex lands in this region, it will intersect the vertex in question.

For 2, x,y will meet iff y arrives within 20 minutes of x's arrival for the two to meet. This gives ypu the equation ##|A(x)-A(y)| \leq 20 ##, for ##A(x),A(y)## arrival times of ##x,y## . This describes a region in the unit square, and its area is equivalent to the probability of meeting. i.e., person 2 comes in, stays 20 minutes and leaves. This means person 1 must come in either (within) 20 minutes before or withn 20 minutes (after) the arrival of person 2 for the two to be able to meet. Now you need to consider the possible arrival times of person 2.

Will be out for a while now, but will return later on tonight.
 
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  • #7
Thanks for the tips .They were quite helpful.:smile:
 
  • #8
Glad they helped :smile:
 

1. What is geometric probability?

Geometric probability is a branch of mathematics that deals with the likelihood of obtaining a certain geometric outcome from a random experiment. It involves calculating the probability of a specific geometric event occurring, such as the length of a line falling within a certain range or the area of a shape meeting certain criteria.

2. What types of problems can be solved using geometric probability?

Geometric probability can be used to solve a variety of problems, such as finding the probability of a point falling within a specific region on a graph, the likelihood of a line segment intersecting another line, or the chance of a shape having a certain area. It can also be used to solve problems in real-world applications, such as estimating the likelihood of a dart landing on a certain section of a dartboard or the probability of a car accident occurring at a particular intersection.

3. How is geometric probability different from other types of probability?

Geometric probability differs from other types of probability, such as classical and empirical probability, in that it deals specifically with geometric outcomes and events. It involves using geometric concepts and formulas, such as areas and volumes, to calculate the likelihood of a certain outcome occurring.

4. What are some common formulas used in solving geometric probability problems?

Some common formulas used in solving geometric probability problems include the area and perimeter formulas for various shapes, such as circles, triangles, and rectangles. Other formulas may involve calculating probabilities using ratios, proportions, or the Pythagorean theorem.

5. Can geometric probability be applied to real-world situations?

Yes, geometric probability can be applied to real-world situations in various fields, such as physics, engineering, and statistics. It can be used to make predictions and estimates, as well as to solve practical problems involving geometric outcomes, such as the probability of a missile hitting its target or the likelihood of a patient surviving a medical procedure.

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