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#### GrannySmith

##### New member

- Jan 5, 2014

- 5

(2+√7)/(3-√-11). What the heck?

I start out by multiplying both sides with the conjugate again. This is where I am stuck lol. Can someone tell me what I am doing wrong while multiplying the conjugate?

(3 - √-11) is the same as 3 - √11i correct? So I multiply (3 - √11i) with (3 + √11i). I don't understand how this goes, but I tried.

3 times 3 is 9.

3 times √11i is 3√11i

-√11i times 3 is -3√11i canceling out 3√11i

-√11i times √11i is -11i? A bit confused on how this works and I'm guessing this is where I made a mistake?

On top we have (2+√7)(3 + √11i).

2 times 3 is 6

2 times √11i is 2√11i

√7 times 3 is 3√7

What would √7 times √11i be? √77i? Can you multiply a normal square root with an imaginary square root?