Pressure Calculation for Water Flow in a Galvanized Iron Pipe System

[dronell90]

Hi I need help solving this problem, If anyone could help me it be great. Thanks

The rate of flow in the pipe system is 0.05 m^3s. The pressure at point 1 is measure to be 260kpa. all the pipes are galvanized iron with roughness value of 0.15 mm. Determine the pressure at point 2. take the loss of coefficient for the sudden contraction as 0.05 and v= 1.141x10^-6 m^2/s

Diameter pt1: 150mm
Length pt1: 300m

Diameter between pt1 and pt2: 270mm
Length between pt1 and pt2: 250m

Diameter pt2: 220mm
Length pt2: 400m.

 

[Valkarie]

Solution:Using the Darcy-Weisbach equation, we can calculate the pressure drop at point 2. The formula is: ΔP = (f * L * ρ * V^2) / (2 * g * D)Where: f = Loss of coefficient (0.05) L = Length of pipe (250m) ρ = Density of fluid (1000 kg/m^3) V = Velocity of fluid (0.05 m^3/s) g = Acceleration due to gravity (9.81 m/s^2) D = Diameter between point 1 and 2 (270mm) Plugging in the values, we get: ΔP = (0.05 * 250 * 1000 * 0.05^2) / (2 * 9.81 * 0.27) ΔP = 11.31 kPa. Therefore, the pressure at point 2 is 260 - 11.31 = 248.69 kPa.