- #1
jaus tail
- 615
- 48
Homework Statement
Homework Equations
I rms for triangular waveform = I(max)/ (1.732)
R = V/I
The Attempt at a Solution
Since there is RLE load, current waveform is triangular. It is
Source current is
Average of I source. I used integration. Assumed Time period = 10 seconds. So T on = 5 seconds. (question says duty = 0.5)
So integrating I got average source current = 14.7 A
Average source voltage = 200 V
So input resistance = 200 / 14.7 = 13.6A
But I'm not able to get the first one. I get answer as 26.33 A But that is not even in the option.
I used formula square I(load) = square dc component (26.05) + square (rms of triangular waveform)
Attachments
Last edited: