Power dissipation in this circuit

In summary, This schematic is more theoretical for design before I build it in an automotive environment. The left hand controller "1" gets its input signal from the sensor (refer to first picture which names the power wires). The sensor will either output high when the truck is moving fast, and low when the truck is moving slow. I am basically being told that the resistance of the wires is important.
  • #1
Destynn
6
0
Hey Guys,

Can you see what is wrong with this circuit?

It looks fine to me but I am being told that it is incorrect and will not work. I am pretty sure I am wrong and am willing to ask for help in understanding why this wouldn't work.

Please see attached picture for further info and any resistances that haven't been provided should be negligible to solving this.

Thanks,
Dest
 

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    Circuit sketch.png
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  • #2
Destynn said:
Hey Guys,

Can you see what is wrong with this circuit?

It looks fine to me but I am being told that it is incorrect and will not work. I am pretty sure I am wrong and am willing to ask for help in understanding why this wouldn't work.

Please see attached picture for further info and any resistances that haven't been provided should be negligible to solving this.

Thanks,
Dest

Welcome to the PF.

What is the context for this question? Is it for schoolwork? The schematic is drawn very unconventionally, and so it is difficult to understand what the connections are. For example, are the right side 2 boxes that are consuming 25A each wired in parallel or in series?
 
  • #3
Yes, it is unconventional and could be interpreted in several ways. How does the left hand controller get its supply? Sensors usually take very little power so what is happening there?
The electricity behaves very literally (it's dumb stuff, in the end) and doesn't know what you want it to do unless you wire it totally correctly so your diagram needs to be done very carefully.
 
  • #4
This schematic is more theoretical for design before I build it in an automotive environment.

I have redrawn it in a hopefully more schematic in a more appropriate way.

To Berke- These are to be wired in series (as shown in my new attached picture).

To Sophie- The left hand controller "1" gets its input signal from the sensor (refer to first picture which names the power wires).
The sensor will either output high when the truck is moving fast, and low when the truck is moving slow.
I am basically being told that the resistance of the wires is important.

Thanks,
Dest
 

Attachments

  • Circuit sketch.png
    Circuit sketch.png
    3.3 KB · Views: 523
  • #5
Destynn said:
This schematic is more theoretical for design before I build it in an automotive environment.

I have redrawn it in a hopefully more schematic in a more appropriate way.

To Berke- These are to be wired in series (as shown in my new attached picture).

To Sophie- The left hand controller "1" gets its input signal from the sensor (refer to first picture which names the power wires).
The sensor will either output high when the truck is moving fast, and low when the truck is moving slow.
I am basically being told that the resistance of the wires is important.

Thanks,
Dest

Several problems/issues:

1) No sensor draws 25 Amps.

2) You don't wire power consumers in series. You wire them with parallel power connections.

3) Is the "25A" that you show for the two controllers their maximum current draw possible, and they typically draw less?
 
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  • #6
Pretty much nothing makes sense about this circuit.

Electricity has a language all of its own.

Are they wired in series and parallel? Looks strange. The red wires with the main power thru them have no ohm rating? Strange again.

I would agree that 75 amps is pretty huge. What are you controlling...a "cruise control system"?
Is this actually in a truck or is it some type of simulation?

To the OP...divulge every piece of information there is so maybe this could be pieced together.

Are you in high school, college...or just a hobbyist in your basement?

Also, if you have 25 amps going thru .9 ohm wires...you just dropped almost 25 volts in three parallel branches. Can't happen with a source of 24 volts. Would not make any sense. You wouldn't have any power left to power your controllers. Or is the .9 ohms suggesting the entire load...that might actually make sense.
 
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  • #7
Actually I figured it out.

First of all I want to thank everyone for their time and efforts. I apologize as well for my lack of having enough information to explain it correctly.

I am just a hobbyist in the basement and this is mainly just a simulation for a "fake" system someone had me make up for educational purposes.

It turns out that the numbers of the currents/voltages/resistance were irrelevant but just to know that if C1 was pulling a very high amperage (ex:450A) and the sensor was pulling very little (ex:1A) why would this setup be incorrect?

The answer was that the sensor should have been grounded over by the negative edge of controller 1 aka to the left of the big stud point where everything is meeting up.

This would make it so that the signal coming off the sensor would have the correct ground reference and it wouldn't read a way different value.

Thanks for everything guys I hope I didn't make everyone's brain 'splode with my inability to explain my problem.

Dest
 
  • #8
First of all, 450 amps requires a HUGE cable. Copper is expensive and heavy. Not to mention finding a battery to deliver that for more than a couple minutes would be tough. To even have an alternator deliver that much power would be expenisve and power robbing to a gas engine. 450 amps at 24 volts would rob your engine of rougly 15 HP for a controller! That's ridiculous. It might take 15 HP to run your air conditioner, but that is reasonable since an compressor takes lots of HP to turn.

2nd of all, controllers and sensors are small amperage devices that typically give signals to high amperage devices...like electric motors. By signals I mean they are basically giving a low voltage, low amperage signal to turn a device on or off for example. So why on Earth would you use 450 amps to do this in your application?

3rdly, your circuit diagram still doesn't make much sense. You need to go back and understand the basics of circuits a little better.

Look at this link and ones similar to it:
http://courses.ncssm.edu/apb11o/resources/guides/G21-5.circuit_multiloop_circuits.htm

The resistors shown are similar to your loads above. Except, it appears you have your loads at the nodes...whereas the resistors are inbetween the nodes (typical of wiring diagrams)

If you drawing had some internal wiring shown on the insides of the loads it might make more sense.
 
Last edited:
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  • #9
Destynn said:
Actually I figured it out.

First of all I want to thank everyone for their time and efforts. I apologize as well for my lack of having enough information to explain it correctly.

I am just a hobbyist in the basement and this is mainly just a simulation for a "fake" system someone had me make up for educational purposes.

It turns out that the numbers of the currents/voltages/resistance were irrelevant but just to know that if C1 was pulling a very high amperage (ex:450A) and the sensor was pulling very little (ex:1A) why would this setup be incorrect?

The answer was that the sensor should have been grounded over by the negative edge of controller 1 aka to the left of the big stud point where everything is meeting up.

This would make it so that the signal coming off the sensor would have the correct ground reference and it wouldn't read a way different value.

Thanks for everything guys I hope I didn't make everyone's brain 'splode with my inability to explain my problem.

Dest

I hope that person are not trying to "educate" live subjects. I can't think how you would input that design into any real simulator.
If you want to simulate or build more circuits then you really should study how people draw them. The net is full of examples of circuit diagrams and they nearly all have very common conventions. (Steer clear of Automotive circuits in manuals; they are often just plain loony. Drawing schematics is a precise language - just as precise as Maths and more so than regular English. Your diagram means so little that it is impossible to assess what it does, I'm afraid.
 
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  • #10
I will take this as a learning lesson and will make sure to make things easier for next time.
 
  • #11
. . . . . . is the right attitude. Good lad.
 

Related to Power dissipation in this circuit

1. What is power dissipation in a circuit?

Power dissipation in a circuit is the amount of energy that is converted into heat when an electrical current flows through the circuit. It is measured in watts (W) and is a crucial factor in determining the efficiency and performance of a circuit.

2. How is power dissipation calculated?

Power dissipation can be calculated using the formula P = I x V, where P is power in watts, I is current in amps, and V is voltage in volts. This formula is known as Joule's Law and is used to determine the amount of heat energy produced in a circuit.

3. What factors affect power dissipation in a circuit?

The main factors that affect power dissipation in a circuit are the current flowing through the circuit, the resistance of the components, and the voltage applied. The higher the current and voltage, and the lower the resistance, the greater the power dissipation will be.

4. How can power dissipation be reduced?

Power dissipation can be reduced by using components with lower resistance, reducing the voltage applied, and using efficient circuit designs. Heat sinks and fans can also be used to dissipate heat from the circuit and prevent overheating.

5. What are the effects of high power dissipation in a circuit?

High power dissipation in a circuit can lead to overheating, which can cause damage to components and decrease the overall efficiency and performance of the circuit. It can also be a safety hazard and cause fires if not properly managed.

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