Potential and work done by the charge

In summary, the conversation discusses the calculation of potential and potential difference between two points due to an electric charge, as well as the change in electric potential energy and the work done by the electric field. The solutions provided involve using the formula VA=kq/r and considering the sign of the charge.
  • #1
xamy
27
0

1. Homework Statement

Tis is my attempt to the question so far. I am not sure about the answers if anyone please confirm them whether I have done the solution correctly or not especially for part 1.4 and 1.6.
Can anyone also guide me about how to do the last part.

1. A chargeQ =-10.0 nC is located 0.30 m from pointA and 0.50 m from pointB.
1.1. What is the potential at A?
1.2. What is the potential atB?
1.3. If a point chargeq is moved fromA toB whileQ is fixed in place, through what potential difference does it move?
1.4. Does its potential increase or decrease?
1.5. Ifq =-26.5 nC, what is the change in electric potential energy as it moves fromA toB?
1.6.Does the potential energy increase or decrease?
1.7. How much work is done by the electric field due to chargeQ as q moves fromA toB?2. The attempt at a solution

1.1
VA=kq/r

=(9x109)(10n)/0.3

=300V

1.2
VB=kq/r


=(9x109)(10n)/0.5

=180V

1.3
ΔV=VA-VB


=300-180

=120V

1.4
Decrease

1.5
ΔUE=qΔV


=(26.5n)(120)

=3.18uJ

1.6
decrease
 
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  • #2
xamy said:

Homework Statement



1. A chargeQ =-10.0 nC is located 0.30 m from pointA and 0.50 m from pointB.
1.1. What is the potential at A?
1.2. What is the potential atB?
1.3. If a point chargeq is moved fromA toB whileQ is fixed in place, through what potential difference does it move?
1.4. Does its potential increase or decrease?
1.5. Ifq =-26.5 nC, what is the change in electric potential energy as it moves fromA toB?
1.6.Does the potential energy increase or decrease?
1.7. How much work is done by the electric field due to chargeQ as q moves fromA toB?2. The attempt at a solution

1.1
VA=kq/r

=(9x109)(10n)/0.3

=300V

You substituted wrong value for the charge - everywhere. The sign of the charge can not be ignored!
 
  • #3
Alright is answer to question 1.4 and 1.6 correct?? Secondly can you guide me how to solve qtn 1.7
 

Related to Potential and work done by the charge

1. What is potential energy of a charge?

The potential energy of a charge is the energy that a charge possesses due to its position in an electric field. It is measured in joules (J) and is calculated by multiplying the charge's electric potential by its magnitude.

2. How is potential energy related to work done by a charge?

Potential energy and work done by a charge are directly related. The work done by a charge is equal to the change in its potential energy. This means that when a charge moves from one point to another in an electric field, its potential energy changes and work is done.

3. Can potential energy of a charge be negative?

Yes, potential energy of a charge can be negative. This occurs when the charge moves in the direction opposite to the direction of the electric field, resulting in a decrease in its potential energy. However, the magnitude of the negative potential energy is still equal to the work done by the charge.

4. How is work done by a charge calculated?

The work done by a charge is calculated by multiplying the charge's electric potential by the distance it moves in the electric field. Mathematically, it is represented as W = qVd, where W is the work done, q is the charge, V is the electric potential, and d is the distance moved.

5. What is the unit of work done by a charge?

The unit of work done by a charge is the joule (J). However, it can also be expressed in electron volts (eV) or kilowatt-hours (kWh). 1 eV is equivalent to 1.6 x 10^-19 J and 1 kWh is equal to 3.6 x 10^6 J.

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