You'd better check that assumption. As you move the object around, the position and size of the image will change.jsalapide said:i come to think of it, the image size does not change no matter what value of p and q is.
A concave mirror is curved inward, with a reflective surface on the inner side. When light rays hit the mirror, they are reflected towards a central focal point. This causes the image to be flipped and magnified because the light rays are converging towards the focal point.
The position of the object can be affected by the distance between the object and the mirror, the curvature of the mirror, and the size of the object. The closer the object is to the mirror and the larger the curvature, the stronger the magnification will be.
No, the object must be placed between the focal point and the center of curvature of the mirror to create an inverted, magnified image. If the object is placed beyond the center of curvature, the image will be inverted but smaller in size.
The position of the object can be calculated using the mirror equation: 1/f = 1/do + 1/di, where f is the focal length of the mirror, do is the distance between the object and the mirror, and di is the distance between the image and the mirror. Rearranging this equation will give you the position of the object, do = f(di-f)/di.
The magnification of the image can be changed by adjusting the distance between the object and the mirror. Moving the object closer to the mirror will increase the magnification, while moving it further away will decrease the magnification. The curvature of the mirror can also be changed to alter the magnification, with a larger curvature resulting in a stronger magnification.